Name the ionization isomer of `[Cr(H_2O)_5Br]SO_4`.

Explanation

To find the ionization isomer of the coordination compound \([Cr(H_2O)_5Br]SO_4\), we will follow these steps:

### Step 1: Identify the given coordination compound
The given compound is \([Cr(H_2O)_5Br]SO_4\). Here, chromium (Cr) is the central metal ion, surrounded by five water molecules (H2O) and one bromide ion (Br), with a sulfate ion (SO4) as the counter ion.

### Step 2: Understand ionization isomers
Ionization isomers are formed when the ligands and counter ions can interchange positions. In this case, the bromide ion (Br) can be exchanged with the sulfate ion (SO4) when the compound is dissolved in water.

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