What type of isomerism is shown by `[Co("edta")]^(-1) and [Co(en)_3]^(3+)` ?

Explanation

To determine the type of isomerism shown by the coordination compounds \([Co(EDTA)]^{-1}\) and \([Co(en)_3]^{3+}\), we need to analyze the ligands and their coordination properties.

### Step-by-Step Solution:

1. **Identify the Ligands**:
- The ligand EDTA (ethylenediaminetetraacetic acid) is a hexadentate ligand, meaning it can form six bonds with the central metal ion (cobalt in this case).
- The ligand en (ethylenediamine) is a bidentate ligand, meaning it can form two bonds with the central metal ion.

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