If the geometry of `[PtCl_4]^(2-)` -is square planar, which orbitals are involved in bonding?

Explanation

To determine which orbitals are involved in bonding for the square planar complex \([PtCl_4]^{2-}\), we will follow these steps:

### Step 1: Determine the oxidation state of platinum (Pt)
Let the oxidation state of Pt be \(X\). The overall charge of the complex is \(-2\), and since there are four chloride ions (each with a charge of \(-1\)), we can set up the following equation:

\[ X + 4(-1) = -2 \]
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