By heating a mixture of `CHCl_3` with silver powder, the compound formed is

Options

A. acetylene
B. silver acetate
C. methanol
D. none of these

Explanation

To solve the question, we need to analyze the reaction that occurs when chloroform (CHCl₃) is heated with silver powder (Ag).

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are chloroform (CHCl₃) and silver powder (Ag).

2. **Understand the Reaction**:
When CHCl₃ is heated with silver powder, the chlorine atoms in chloroform can react with silver to form silver chloride (AgCl). This is a substitution reaction where chlorine is removed.

3. **Write the Reaction**:
The reaction can be represented as:
\[ 6 \, \text{CHCl}_3 + 6 \, \text{Ag} \rightarrow 6 \, \text{AgCl} + 2 \, \text{C}_2\text{H}_2 \]
Here, the chlorine atoms are replaced by hydrogen atoms, leading to the formation of acetylene (C₂H₂).

4. **Identify the Product**:
The primary product formed from this reaction is acetylene (C₂H₂), along with silver chloride (AgCl) as a byproduct.

5. **Conclusion**:
Therefore, when a mixture of CHCl₃ is heated with silver powder, the compound formed is acetylene (C₂H₂).

### Final Answer:
The compound formed is **acetylene (C₂H₂)**.

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