Which one is formed when sodium phenoxide is heated with ethyl iodide ?

Options

A. Phenetole
B. Ethyl phenyl alcohol
C. Phenol
D. None of these.

Explanation

To solve the question of what is formed when sodium phenoxide is heated with ethyl iodide, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are sodium phenoxide (C6H5ONa) and ethyl iodide (C2H5I).

### Step 2: Understand the Reaction Type
This reaction is an example of the Williamson ether synthesis, which involves the reaction of an alkoxide (sodium phenoxide) with an alkyl halide (ethyl iodide) to form an ether.

### Step 3: Write the Reaction
The reaction can be represented as follows:
\[ \text{C}_6\text{H}_5\text{ONa} + \text{C}_2\text{H}_5\text{I} \rightarrow \text{C}_6\text{H}_5\text{O}\text{C}_2\text{H}_5 + \text{NaI} \]

### Step 4: Identify the Products
From the reaction, we can see that the product formed is phenethyl ether, which is also known as phenetole (C6H5O-C2H5). The byproduct of this reaction is sodium iodide (NaI).

### Step 5: Conclusion
Thus, when sodium phenoxide is heated with ethyl iodide, the product formed is phenetole.

### Final Answer
The answer to the question is **phenetole**.

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