Supply formulae for the organic products from the reaction of `CH_3 C -= C^(-) Na^(+) + CH_3CH_2 CH_2 Cl`

Explanation

To solve the problem, we will analyze the reaction between the alkyne anion \( CH_3C \equiv C^{-}Na^{+} \) and the alkyl halide \( CH_3CH_2CH_2Cl \).

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The first reactant is an alkyne anion: \( CH_3C \equiv C^{-} \) (propyne anion).
- The second reactant is an alkyl halide: \( CH_3CH_2CH_2Cl \) (1-chloropropane).

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