Arrange `1^(@),2^(@),3^(@)` liquid alcohols in decreasing order of acidities.

Explanation

To arrange the 1° (primary), 2° (secondary), and 3° (tertiary) liquid alcohols in decreasing order of acidity, we need to consider the stability of the alkoxide ion that forms when the alcohol loses a proton (H⁺). The acidity of alcohols is influenced by the stability of this alkoxide ion, which is affected by the electron-donating or electron-withdrawing effects of the alkyl groups attached to the hydroxyl (-OH) group.

### Step-by-Step Solution:

1. **Understand Alcohol Structure**:
- Primary alcohol (1°): R-CH2OH (where R is an alkyl group)
- Secondary alcohol (2°): R1-CHOH-R2 (where R1 and R2 are alkyl groups)
- Tertiary alcohol (3°): R1R2R3C-OH (where R1, R2, and R3 are alkyl groups)
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