Of the two alcohols, (a) `CH_(2)=CH-CH_(2)OH` and (b) `CH_(2)=CH-CH_(2)-CH_(2)OH`, which one will react more easily with conc. HCl in the presence of `ZnCl_(2)`?

Explanation

To determine which of the two alcohols, (a) `CH2=CH-CH2OH` (propan-2-ol) and (b) `CH2=CH-CH2-CH2OH` (butan-2-ol), reacts more easily with concentrated HCl in the presence of ZnCl2, we can follow these steps:

### Step 1: Identify the Type of Alcohols
Both alcohols are secondary alcohols.
- (a) `CH2=CH-CH2OH` has a carbon chain of 3 carbons (propan-2-ol).
- (b) `CH2=CH-CH2-CH2OH` has a carbon chain of 4 carbons (butan-2-ol).

### Step 2: Understand the Reaction with Lucas Reagent
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