Name the type of isomerism exhibited by the following pair of compounds:
1-Butanol and 2-methyl-1-propanol.

Explanation

To determine the type of isomerism exhibited by 1-butanol and 2-methyl-1-propanol, we can follow these steps:

### Step 1: Write the Structures of the Compounds
- **1-Butanol**: The structure is CH3-CH2-CH2-CH2-OH. This indicates a straight-chain alcohol with four carbon atoms.
- **2-Methyl-1-Propanol**: The structure is CH3-CH(CH3)-CH2-OH. This indicates a branched-chain alcohol with three carbon atoms in the longest chain and a methyl group attached to the second carbon.

### Step 2: Analyze the Carbon Skeletons
- In 1-butanol, the longest carbon chain consists of four carbon atoms.
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