Phosphorus exhibits a covalency of 3 in `PCI_3` while of 5 in `PCI_5`. How would account for this observation?

What type of hybridization is involved in PCI_5 ?

A quantity of PCI_(5) was heated in a 10 litre vessel at 250^(@)C, PCI_(5)(g)hArrPCI_(3)(g) + CI_(2)(g) . At equilibrium the vessel contains 0.1 mole of PCI_(5), 0.20 mole of PCI_(3) and 0.2 mole of CI_(2) . The equilibrium constant of the reaction is

Phenol reacts with PCI_(5) , the main product is:

Oxidation state of phosphorus in PCl_3 is ……………… and in PCl_5 is ……………. .

For the dissociation of PCI_(5) into PCI_(3) and Cl_(2) in gaseous phase reaction, If "d' is the observed vapour density and 'D' theoretical vapour density with 'alpha' as degree of dissociation. Variation of (D)/(d) with 'alpha' is given by which graph?

A hemispherical bowl has a radius of 3.5 cm. What would be the volume of water it would contain?

A quantity of PCI _5 was heated in a 2 litre vessel at 525 K . It dissociates as PCI_5 (g) hArr PCI _3 (g) + CI_2 (g) At equilibrium 0.2 mol each of PCI_5 , PCl_3and Cl_2 is found in the reaction mixture. The equilibrium constant K_c for the reaction is -

In solid state, PCI_5 , is a

AICI_(3) is covalent while AIF_(3) is ionic This can be justified on the basic of .

Can phosphorus with outer electronic configureation 3s^2 3p^3 " form "PH_5 ?