Write the ground state electronic configuration of `F_(2)^(+)`.

Magnesium reacts with an element (x) to form an ionic compound. If the ground state electronic configuration of (X) is 1s^2 2s^2 2p^3 , the simplest formula for this compound is

The element having the lowest atomic number and a ground state electronic configuration of (n-1) d^(6)ns^(2) is placed in:

The ground state electronic configuration of S is 3s^(2) 3 p^(4) . How does it form the compound SF_(6) ?

Write down the electronic configuration of: Co ^(2+)

Write down the electronic configuration of: Ce ^(4+)

From the ground state electronic configuration of the elements given below, pick up the one with the highest value of second ionisation energies

The representation of the ground state electronic configuration of He by box diagram as is wrong because it violates

From the ground state, electronic configuration of the elements given below, pick up the one with highest value of second ionization energy:

Answer the following on the basis of modern periodic table. (I) Group no. of elements with the valence shell ground state electron configuration ns^(2)np^(5) (II) Group no. of the elements with the valence shell ground state electron configuratio ns^(2)np^(3) (III) Group no. of the elements that have only three unpaired p electron in ground state (V) ground 3A elements.

Answer the following on the basis of modern periodic table. (I) Group no. of elements with the valence shell ground state electron configuration ns^(2)np^(5) (II) Group no. of the elements with the valence shell ground state electron configuratio ns^(2)np^(3) (III) Group no. of the elements that have only three unpaired p electron in ground state