Write the state of hybridisation of nitrogen in `NO_(3)^(-)` ion.

Explanation

To determine the state of hybridization of nitrogen in the nitrate ion \((NO_3^−)\), we can follow these steps:

### Step 1: Determine the Lewis Structure of \(NO_3^−\)

1. **Count the total number of valence electrons**:
- Nitrogen (N) has 5 valence electrons.
- Each oxygen (O) has 6 valence electrons, and there are three oxygen atoms, contributing \(3 \times 6 = 18\) electrons.
- The negative charge adds 1 additional electron.
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