Why are the molecules like `He_2 , H_3 and H_4` not formed?

Formation of a solution from two components can be considered as : (i) pure solvent rarr separated solvent molecules, /_\H_(1) (ii) Pure solute rarr separated molecules, /_\H_(2) (iii) separated solvent and solute molecules rarr solution, /_\H_(3) solution so formed will be ideal if :

In the following questions, a statement of assertion (A) is followed by a statement of reason (R ) A : Each molecule of H_(2)O forms four H-bond in the form of ice. R : ice is solid state of H_(2)O .

1 molecule glucose, 6 molecules of O_(2) and 38 ADP combine to form 6H_(2)O,6CO_(2) , and

On the basis of VSEPR theory explain why BeCl_2 molecule is linear whereas H_2 O is angular.

Consider the following molecules : H_(2)O ,H_(2)S ,H_(2) Se ,H_(2)Te Arrange these molecules in increasing order of acidity

Assertion : H_(2) molecule is more stable than He-H molecule . Reason : The antibonding electron in He-H molecule decreases the bond order thereby the stability.

Gases like CO_(2) and CH_(4) show more deviation from the ideal gas behaviour as compared to gases like H_(2) and He , Explain

Explain the formation of following molecules : PCl_3 ,CH_4 ,H_2 O , PH_3 , OF_2 , C_2 H_6

In the reaction ._1^2 H + ._1^3 H rarr ._2^4 He + ._0^1 n , if the binding energies of ._1^2 H, ._1^3 H and ._2^4 He are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is.

In the reaction ._1^2 H + ._1^3 H rarr ._2^4 He + ._0^1 n , if the binding energies of ._1^2 H, ._1^3 H and ._2^4 He are respectively a,b and c (in MeV), then the energy (in MeV) released in this reaction is.