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The geometry of H2S and its dipole momen...

The geometry of `H_2S` and its dipole moment are

A

angular and non-zero

B

angular and zero

C

linear and non-zero

D

linear and zero.

Text Solution

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The correct Answer is:
To determine the geometry of H₂S (hydrogen sulfide) and its dipole moment, we can follow these steps: ### Step 1: Determine the Valence Electrons - Sulfur (S) is the central atom and belongs to Group 16 of the periodic table, which means it has 6 valence electrons. - Each hydrogen (H) atom has 1 valence electron, and there are 2 hydrogen atoms, contributing a total of 2 valence electrons. **Total Valence Electrons = Valence Electrons of S + Valence Electrons of H** \[ = 6 + 2 = 8 \text{ valence electrons} \] **Hint:** Remember to count the valence electrons for each atom based on their group number in the periodic table. ### Step 2: Calculate the Steric Number - The steric number can be calculated using the formula: \[ \text{Steric Number} = \frac{1}{2} \left( V + M + C \right) \] Where: - \( V \) = number of valence electrons of the central atom (S = 6) - \( M \) = number of monovalent atoms attached (H = 2) - \( C \) = charge (0 for neutral molecules) Substituting the values: \[ \text{Steric Number} = \frac{1}{2} \left( 6 + 2 + 0 \right) = \frac{8}{2} = 4 \] **Hint:** The steric number helps determine the hybridization and geometry of the molecule. ### Step 3: Determine Hybridization - A steric number of 4 indicates that the hybridization of the central atom (S) is \( sp^3 \). **Hint:** The hybridization can be inferred from the steric number (e.g., 4 corresponds to \( sp^3 \)). ### Step 4: Identify the Geometry - With \( sp^3 \) hybridization and 2 bond pairs (from H atoms) and 2 lone pairs, the geometry is tetrahedral. - However, the presence of lone pairs affects the shape. The actual shape of H₂S is bent (or angular) due to the repulsion from the lone pairs. **Hint:** The shape of the molecule can differ from its geometry due to lone pairs. ### Step 5: Determine the Dipole Moment - In H₂S, sulfur is more electronegative than hydrogen, creating a dipole moment directed towards the sulfur atom. - Since the individual dipole moments do not cancel out completely due to the bent shape, the overall dipole moment of H₂S is non-zero. **Hint:** The dipole moment depends on the electronegativity difference and the molecular shape. ### Conclusion - The geometry of H₂S is bent (angular) and it has a non-zero dipole moment. **Final Answer:** The correct option is "angular and non-zero".

To determine the geometry of H₂S (hydrogen sulfide) and its dipole moment, we can follow these steps: ### Step 1: Determine the Valence Electrons - Sulfur (S) is the central atom and belongs to Group 16 of the periodic table, which means it has 6 valence electrons. - Each hydrogen (H) atom has 1 valence electron, and there are 2 hydrogen atoms, contributing a total of 2 valence electrons. **Total Valence Electrons = Valence Electrons of S + Valence Electrons of H** \[ ...
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