The molecular shapes of `SF_4, CF_4 and XeF_4` are

Options

A. different with 1, 0 and 2 lone pairs of electrons on the central atom, respectively
B. different with 0, 1 and 2 lone pairs of electrons on the central atom, respectively
C. the same with 1, 1 and 1 lone pair of electrons on the central atom, respectively
D. the same with 2,0 and 1 lone pairs of electrons on the central atom, respectively.

Explanation

To determine the molecular shapes of SF₄, CF₄, and XeF₄, we will follow these steps:

### Step 1: Determine the Steric Number for SF₄
1. **Identify the central atom and its valence electrons**: Sulfur (S) has 6 valence electrons.
2. **Count the number of monovalent atoms attached**: There are 4 fluorine (F) atoms attached to sulfur.
3. **Calculate the steric number** using the formula:
\[ \text{Steric Number} = \frac{(V + M)}{2} \]
where \(V\) is the number of valence electrons and \(M\) is the number of monovalent atoms.
\[ \text{Steric Number} = \frac{(6 + 4)}{2} = \frac{10}{2} = 5 \]

### Step 2: Determine the Hybridization and Shape for SF₄
1. **Identify the hybridization**: With a steric number of 5, the hybridization is sp³d.
2. **Determine the number of lone pairs**: Since there are 4 bond pairs (from the 4 F atoms) and 1 lone pair, the molecular shape is **seesaw**.

### Step 3: Determine the Steric Number for CF₄
1. **Identify the central atom and its valence electrons**: Carbon (C) has 4 valence electrons.
2. **Count the number of monovalent atoms attached**: There are 4 fluorine (F) atoms attached to carbon.
3. **Calculate the steric number**:
\[ \text{Steric Number} = \frac{(4 + 4)}{2} = \frac{8}{2} = 4 \]

### Step 4: Determine the Hybridization and Shape for CF₄
1. **Identify the hybridization**: With a steric number of 4, the hybridization is sp³.
2. **Determine the number of lone pairs**: There are 4 bond pairs and 0 lone pairs, so the molecular shape is **tetrahedral**.

### Step 5: Determine the Steric Number for XeF₄
1. **Identify the central atom and its valence electrons**: Xenon (Xe) has 8 valence electrons.
2. **Count the number of monovalent atoms attached**: There are 4 fluorine (F) atoms attached to xenon.
3. **Calculate the steric number**:
\[ \text{Steric Number} = \frac{(8 + 4)}{2} = \frac{12}{2} = 6 \]

### Step 6: Determine the Hybridization and Shape for XeF₄
1. **Identify the hybridization**: With a steric number of 6, the hybridization is sp³d².
2. **Determine the number of lone pairs**: There are 4 bond pairs and 2 lone pairs, so the molecular shape is **square planar**.

### Summary of Molecular Shapes
- **SF₄**: Seesaw (1 lone pair)
- **CF₄**: Tetrahedral (0 lone pairs)
- **XeF₄**: Square planar (2 lone pairs)

### Final Answer
The molecular shapes of SF₄, CF₄, and XeF₄ are seesaw, tetrahedral, and square planar, respectively.