In which of the following ionisation processes, the bond order has increased and the magnetic behaviour has changed?

Options

A. `C_2 to C_(2)^(+)`
B. `NO to NO^(+)`
C. `O_(2) to O_(2)^(+)`
D. `N_2 to N_(2)^(+)`

Answer

B

Explanation

The molecular orbital electronic configurations, bond orders and magnetic behaviour are as follows:
` NO : KK ( sigma_(2s))^2 ( sigma_(2s))^2 ( pi _(2p_x))^2 ( pi _(2p_y))^2 ( sigma_(2pz))^2 ( pi _(2p_x))^1`
Bond order =`(N_b-N_a)/(2) = (8-3)/(2 ) = 2 (1)/(2)`
Magnetic behaviour = Paramagnetic
NO^(+) : KK ( sigma_(2s))^2 ( simga_(2s))^2 ( pi _(2p_x))^2 ( sigma_(2p_z)^2)`
bond order `= (N_b - N_a)/(2) = ( 8-2 )/(2 )=3`
Magnetic behaviour = Diamagnetic
Thus, during the process NO `to NO^(+)`, the bond order has increased and the magnetic behaviour has changed.