The bond order of `O_(2)^(2-)` ion is ............ and the ion is .......... magnetic in nature.

Explanation

To find the bond order of the \( O_2^{2-} \) ion and determine its magnetic nature, we will follow these steps:

### Step 1: Determine the total number of electrons in \( O_2^{2-} \)
- Each oxygen atom has 8 electrons. Therefore, for two oxygen atoms, the total number of electrons is \( 8 + 8 = 16 \).
- The \( O_2^{2-} \) ion has 2 additional electrons, so the total number of electrons is \( 16 + 2 = 18 \).

### Step 2: Write the molecular orbital configuration for \( O_2^{2-} \)
- The molecular orbital filling order for \( O_2 \) is as follows:
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