Calculate the volume strength of a hydrogen peroxide solution containing `60.7 g L^(-1)` of `H_(2)O_(2)`.

Explanation

Hydrogen peroxide decomposes according to the equation
`underset(68g)(2H_(2)O_(2))to2H_(2)O+underset(22.4 "at S.T.P.")(O_(2))`
`because` 68 g of `H_(2)O_(2)` give `O_(2)` at S.T.P=22.4 L
`therefore` 60.7 g of `H_(2)O_(2)` will give `O_(2)` at S.T.P `=(22.4)/68xx60.7`
`=19.995=20L`
Since, 60. 7 g of `H_(2)O_(2)` contained in one litre of the given solution gives 20 L of `O_(2)` at S.T.P., the strength of the given solution is .20 volume..