The strength of `H_(2)O_(2)` is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of `H_(2)O_(2)` on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of `H_(2)O_(2)`gives 10 litre of `O_(2)` at 1 atm and 273 K The decomposition of `H_(2)O_(2)` is shown as under :
`H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g)`
`H_(2)O_(2)` can acts as oxidising as well as reducing agent. As oxidizing agent `H_(2)O_(2)` is converted into `H_(2)O` and as reducing agent `H_(2)O_(2)` is converted into `O_(2)`. For both cases its n-factor is 2. `:. "Normality " " of " H_(2)O_(2)` solution `=2xx "molarity of" H_(2)O_(2)` solution
What is thepercentage strength (%w/V) of "11.2 V" `H_(2)O_(2)`

Options

A. 0.017
B. 0.34
C. 0.034
D. 13.6%.

Answer

C