During the electrolysis of fused sodium hydride, hydrogen gets liberated at cathode.

Answer

To determine whether the statement "During the electrolysis of fused sodium hydride, hydrogen gets liberated at the cathode" is correct or not, we can analyze the process step by step.

### Step-by-Step Solution:

1. **Understanding Electrolysis**:
- Electrolysis is a process that uses electrical energy to drive a non-spontaneous chemical reaction. In this case, we are dealing with fused sodium hydride (NaH).

2. **Dissociation of Sodium Hydride**:
- When sodium hydride is melted (fused), it dissociates into its constituent ions:
\[ \text{NaH} \rightarrow \text{Na}^+ + \text{H}^- \]
- Here, Na⁺ is the sodium ion, and H⁻ is the hydride ion.

3. **Movement of Ions**:
- In electrolysis, the positively charged ions (Na⁺) migrate towards the cathode (the negatively charged electrode), while the negatively charged ions (H⁻) migrate towards the anode (the positively charged electrode).

4. **Reactions at the Electrodes**:
- At the **cathode** (negative electrode):
- The sodium ions (Na⁺) undergo reduction (gain electrons) to form sodium metal:
\[ \text{Na}^+ + e^- \rightarrow \text{Na} \]
- Thus, sodium metal is deposited at the cathode.

- At the **anode** (positive electrode):
- The hydride ions (H⁻) undergo oxidation (lose electrons) to produce hydrogen gas:
\[ 2 \text{H}^- \rightarrow \text{H}_2 + 2 e^- \]
- Therefore, hydrogen gas is liberated at the anode.

5. **Conclusion**:
- The statement in question claims that hydrogen gas is liberated at the cathode, which is incorrect. In reality, hydrogen gas is liberated at the anode during the electrolysis of fused sodium hydride.

### Final Answer:
The statement is **incorrect**; hydrogen gas is liberated at the **anode**, not at the cathode.

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