The perimeter of an isosceles triangle is 49 m and the length of one of its equal sides is 17m. Find the length of the base of the triangle.

Answer

To find the length of the base of the isosceles triangle, we can follow these steps:

### Step-by-step Solution:

1. **Understand the Problem**: We know the perimeter of the isosceles triangle and the length of one of its equal sides. We need to find the length of the base.

2. **Identify Given Values**:
- Perimeter (P) = 49 m
- Length of one equal side (A) = 17 m

3. **Use the Perimeter Formula**:
The formula for the perimeter of an isosceles triangle is:
\[ P = 2A + B \]
where \( A \) is the length of the equal sides and \( B \) is the length of the base.

4. **Substitute the Known Values**:
Substitute the known values into the perimeter formula:
\[ 49 = 2(17) + B \]

5. **Calculate the Value of \( B \)**:
- First, calculate \( 2 \times 17 \):
\[ 2 \times 17 = 34 \]
- Now, substitute this back into the equation:
\[ 49 = 34 + B \]
- To find \( B \), subtract 34 from both sides:
\[ B = 49 - 34 \]
- Calculate \( B \):
\[ B = 15 \]

6. **Conclusion**:
The length of the base of the triangle is \( 15 \) meters.

### Final Answer:
The length of the base of the triangle is **15 meters**.