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If the area of a rectangle is 320 sq. m ...

If the area of a rectangle is 320 sq. m and its length is 20 m, find its breadth and perimeter.

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To solve the problem step by step, we will first find the breadth of the rectangle using the area formula, and then we will calculate the perimeter. ### Step 1: Understand the formula for the area of a rectangle. The area \( A \) of a rectangle is given by the formula: \[ A = \text{length} \times \text{breadth} \] ### Step 2: Substitute the known values into the area formula. We know the area \( A = 320 \, \text{sq. m} \) and the length \( L = 20 \, \text{m} \). We can substitute these values into the formula: \[ 320 = 20 \times \text{breadth} \] ### Step 3: Solve for the breadth. To find the breadth, we will rearrange the equation: \[ \text{breadth} = \frac{320}{20} \] Calculating this gives: \[ \text{breadth} = 16 \, \text{m} \] ### Step 4: Calculate the perimeter of the rectangle. The formula for the perimeter \( P \) of a rectangle is: \[ P = 2 \times (\text{length} + \text{breadth}) \] Substituting the known values: \[ P = 2 \times (20 + 16) \] ### Step 5: Simplify the expression for the perimeter. Calculating inside the parentheses first: \[ P = 2 \times 36 \] Now, multiplying: \[ P = 72 \, \text{m} \] ### Final Answer: - The breadth of the rectangle is \( 16 \, \text{m} \). - The perimeter of the rectangle is \( 72 \, \text{m} \). ---
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