The lid of a rectangular box of sides `30cm` by `15 cm` is sealed all around with tape. What is the length of the tape required to seal the lid?

Options

A. `90cm`
B. `80cm`
C. `60cm`
D. `70cm`

Answer

To find the length of tape required to seal the lid of a rectangular box with dimensions 30 cm by 15 cm, we need to calculate the perimeter of the rectangle. Here’s how to do it step by step:

### Step 1: Identify the dimensions of the rectangle
The dimensions of the rectangular box are given as:
- Length (L) = 30 cm
- Breadth (B) = 15 cm

### Step 2: Use the formula for the perimeter of a rectangle
The formula for the perimeter (P) of a rectangle is:
\[ P = 2 \times (L + B) \]

### Step 3: Substitute the values into the formula
Now, substitute the values of length and breadth into the formula:
\[ P = 2 \times (30 \, \text{cm} + 15 \, \text{cm}) \]

### Step 4: Calculate the sum of length and breadth
First, calculate the sum of the length and breadth:
\[ 30 \, \text{cm} + 15 \, \text{cm} = 45 \, \text{cm} \]

### Step 5: Multiply by 2 to find the perimeter
Now, multiply the sum by 2:
\[ P = 2 \times 45 \, \text{cm} = 90 \, \text{cm} \]

### Conclusion
The length of the tape required to seal the lid of the box is:
\[ \text{Length of tape} = 90 \, \text{cm} \]

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