`(1)/(4)` of 2m = _________cm

Fill in the blank 4 sq. m = "_____________" sq. cm

The quantum number of electrons are given below: Arrange then in order of increasing energies a. n= 4,l= 2,m_(1)= -2, m_(s)= -(1)/(2) b. n= 3,l= 2,m_(1) = 1, m_(s)= +(1)/(2) c. n= 4,l= 1,m_(1) = 0, m_(s)= +(1)/(2) e.n= 3,l= 2,m_(1)= -2, m_(s)= +(1)/(2) f. n= 4,l= 1,m_(1) = +1, m_(s)= +(1)/(2)

If l : m = 2 (1)/(2) : 1(2)/(3) and m : n = 1 (1)/(4) : 3 (1)/(2) , find l : m : n

Find the ratio of each of the in simplest form : 1 m 44 cm to 2 m 40 cm

sum_(m=1)^(n) tan^(-1) ((2m)/(m^(4) + m^(2) + 2)) is equal to

Three particles of masses m , m and 4kg are kept at a verticals of triangle ABC . Coordinates of A , B and C are (1,2) , (3,2) and (-2,-2) respectively such that the centre of mass lies at origin. Find the value of mass m . Hint. x_(cm)=(sum_(i-1)^(3)m_(i)x_(i))/(sum_(i=1)^(3)m_(i)) , y_(cm)=(sum_(i=1)^(3)m_(i)y_(i))/(sum_(i=1)^(3)m_(i))

Three particles of masses m , m and 4kg are kept at a verticals of triangle ABC . Coordinates of A , B and C are (1,2) , (3,2) and (-2,-2) respectively such that the centre of mass lies at origin. Find the value of mass m . Hint. x_(cm)=(sum_(i-1)^(3)m_(i)x_(i))/(sum_(i=1)^(3)m_(i)) , y_(cm)=(sum_(i=1)^(3)m_(i)y_(i))/(sum_(i=1)^(3)m_(i))

If A B C D E F such that D E=3c m , E F=2c m , D F=2. 5 c m , B C=4c m , then perimeter of A B C is (a) 18cm (b) 20cm (c) 12cm (d) 15cm

Two bodies of masses 1kg and 3kg are lying in xy plane at (0,0) and (2,-1) respectively. What are the coordinates of the centre of mass ? Hint. x_(cm)=(m_(1)x_(1)+m_(2)x_(2))/(m_(1)+x_(2)) , y_(cm)=(m_(1)y_(1)+m_(2)y_(2))/(m_(1)+m_(2))

A B C is a right angled triangle, right angled at B such that B C=6c m and A B=8c m . A circle with centre O is inscribed in A B C . The radius of the circle is (a) 1cm (b) 2cm (c) 3cm (d) 4cm