In an election, there are two candidates A and B. The total number of voters is 60,000 and `80%`of the total votes are polled. If `60%` of the polled votes were cast in favour of A, how many votes were polled in favour of B?

Answer

To solve the problem step by step, we will follow the information given in the question.

### Step 1: Calculate the total number of votes polled
The total number of voters is 60,000 and 80% of them voted.

\[ \text{Votes polled} = 80\% \text{ of } 60,000 = \frac{80}{100} \times 60,000 \]

Calculating this gives:

\[ \text{Votes polled} = 0.8 \times 60,000 = 48,000 \]

### Step 2: Determine the number of votes in favor of candidate A
It is given that 60% of the polled votes were cast in favor of candidate A.

\[ \text{Votes for A} = 60\% \text{ of } 48,000 = \frac{60}{100} \times 48,000 \]

Calculating this gives:

\[ \text{Votes for A} = 0.6 \times 48,000 = 28,800 \]

### Step 3: Calculate the number of votes in favor of candidate B
Since there are only two candidates, the remaining votes will be for candidate B. The percentage of votes for B is:

\[ \text{Votes for B} = 100\% - 60\% = 40\% \]

Now, we calculate the number of votes for B:

\[ \text{Votes for B} = 40\% \text{ of } 48,000 = \frac{40}{100} \times 48,000 \]

Calculating this gives:

\[ \text{Votes for B} = 0.4 \times 48,000 = 19,200 \]

### Final Answer
The number of votes polled in favor of candidate B is **19,200**.

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