The population of a city increased by `10%` in the previous year. If the present population is 1,32,000, what was the population of the city a year ago?

Answer

To find the population of the city a year ago, we can follow these steps:

### Step 1: Define the variables
Let the population of the city a year ago be \( x \).

### Step 2: Set up the equation
According to the problem, the population increased by 10%. This means the current population can be expressed as:
\[ x + 10\% \text{ of } x = 132,000 \]
This can also be written as:
\[ x + \frac{10}{100} \times x = 132,000 \]

### Step 3: Simplify the equation
We can simplify the equation:
\[ x + \frac{10}{100} x = 132,000 \]
This simplifies to:
\[ x + 0.1x = 132,000 \]
Combining like terms gives:
\[ 1.1x = 132,000 \]

### Step 4: Solve for \( x \)
To find \( x \), divide both sides of the equation by 1.1:
\[ x = \frac{132,000}{1.1} \]

### Step 5: Calculate the value
Now, performing the division:
\[ x = 120,000 \]

### Conclusion
The population of the city a year ago was \( 120,000 \).

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