A company intoduces a special packing of mixed fruit juice with `15%` extra juice at no extra cost. If the special pack contains 575mL of juice, find the content of the standard pack.

Answer

To find the content of the standard pack of mixed fruit juice, we can follow these steps:

### Step 1: Define the variables
Let the content of the standard pack be \( x \) mL.

### Step 2: Understand the extra juice
The special pack contains 15% extra juice compared to the standard pack. This means that the amount of juice in the special pack can be expressed as:
\[ \text{Special Pack} = \text{Standard Pack} + 15\% \text{ of Standard Pack} \]
This can be written mathematically as:
\[ \text{Special Pack} = x + \frac{15}{100} \times x \]

### Step 3: Simplify the equation
We can combine the terms on the right side:
\[ \text{Special Pack} = x + 0.15x = 1.15x \]

### Step 4: Set up the equation
According to the problem, the special pack contains 575 mL of juice. Therefore, we can set up the equation:
\[ 1.15x = 575 \]

### Step 5: Solve for \( x \)
To find \( x \), divide both sides of the equation by 1.15:
\[ x = \frac{575}{1.15} \]

### Step 6: Calculate the value
Now, we perform the division:
\[ x = 500 \]

### Conclusion
The content of the standard pack is \( 500 \) mL.