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A bag has 7 white, 12 green and 9 blue m...

A bag has 7 white, 12 green and 9 blue marbles. One marble is drawn at random. Find the probability that the marble drawn from the bag is not white.

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To find the probability that the marble drawn from the bag is not white, we can follow these steps: ### Step 1: Calculate the total number of marbles in the bag. - The bag contains: - 7 white marbles - 12 green marbles - 9 blue marbles **Total number of marbles = Number of white marbles + Number of green marbles + Number of blue marbles** \[ \text{Total} = 7 + 12 + 9 = 28 \] ### Step 2: Calculate the number of marbles that are not white. - The marbles that are not white include: - 12 green marbles - 9 blue marbles **Total number of non-white marbles = Number of green marbles + Number of blue marbles** \[ \text{Non-white} = 12 + 9 = 21 \] ### Step 3: Calculate the probability of drawing a marble that is not white. - The probability \( P \) of an event is given by the formula: \[ P(\text{not white}) = \frac{\text{Number of non-white marbles}}{\text{Total number of marbles}} \] Substituting the values we found: \[ P(\text{not white}) = \frac{21}{28} \] ### Step 4: Simplify the fraction. - To simplify \( \frac{21}{28} \), we can divide both the numerator and the denominator by their greatest common divisor (GCD), which is 7: \[ P(\text{not white}) = \frac{21 \div 7}{28 \div 7} = \frac{3}{4} \] ### Final Answer: The probability that the marble drawn from the bag is not white is \( \frac{3}{4} \). ---
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