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The vector vec(F ) is a force of 3.0 ne...

The vector `vec(F )` is a force of `3.0` newton making an angle of `60^(@)` with the displacement . `vec(R )` of magnitude `4.0` m , find
the value of the dot product `vec(F) . vec (R )`

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The correct Answer is:
6 Nm
`vec(F) . vec(R ) = FR cos theta = 3 xx 4 xx cos 60^(@) = 6 Nm . vec(R ) xx vec(F) = 3xx 4 xx sin 60 = 6sqrt(3)` Nm
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ICSE-VECTORS SCALARS ELEMENTARY CALCULUS -FROM SCALAR PRODUCT AND VECTOR PRODUCT
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