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A wire 10m long has a cross-sectional ar...

A wire 10m long has a cross-sectional area `1.25 xx 10^(-4) m^(2)`. It is subjected to a load of 5kg. Wt. If Y for the material is `4 xx 10^(10) Nm^(-2)`, calculate the elongation produced in the wire. Take g = `10 ms^(-2)`.

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To solve the problem of calculating the elongation produced in a wire subjected to a load, we will follow these steps: ### Step 1: Identify the given values - Length of the wire (L) = 10 m - Cross-sectional area (A) = \(1.25 \times 10^{-4} \, m^2\) - Load (mass) = 5 kg - Young's modulus (Y) = \(4 \times 10^{10} \, N/m^2\) - Acceleration due to gravity (g) = \(10 \, m/s^2\) ...
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