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A mass of 20kg is attached to one end of...

A mass of 20kg is attached to one end of a steel wire 50cm long and is rotated in a horizontal circle. The area of cross-section of the wrie is `10^(-6) m^(2)` and the breaking stress for it is `4.8 xx 10^(7) `Pa. Calculate the maximum velocity with which the mass can be rotated.

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To solve the problem, we need to find the maximum velocity with which a mass can be rotated in a horizontal circle while being attached to a steel wire. We will use the concepts of centripetal force and breaking stress. Here’s the step-by-step solution: ### Step 1: Identify the given values - Mass (m) = 20 kg - Length of the wire (r) = 50 cm = 0.50 m - Area of cross-section (A) = \(10^{-6} \, m^2\) - Breaking stress (σ) = \(4.8 \times 10^7 \, Pa\) ...
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