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A square lead slab of sides 50cm and thi...

A square lead slab of sides 50cm and thickness 5.0cm is subjected to a shearing force ( on its narrow face ) of magnitude `9.0 xx 10^(4) N` . The lower edge is riveted to the floor. How much is the upper edge displaced if the shear modulus of lead is `5.6 xx 10^(9)Pa` ?

Text Solution

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`F = 9 xx 10^(4) N` Rigidly modulus `= n = 5.6 xx 10^(9) Pa`
Shearing strain ` theta = ?`
`n = ( F )/( A theta ) , theta = ( F )/( An )`
`theta = ( 9 xx 10^(4))/( 0.025 xx 5.6 xx 10^(9))`
`= 6.428 xx 10^(-4) ` radian
From Figure `x = 1 theta , l = 0.5 m`

`x = 0.5 xx 6.428 xx 10^(-4) `
`= 3.2 xx 10^(-4) m`
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