A load of 2 kg produces a certain extension in a wire of length 6m and diameter 1mm. What is the lateral contraction produced if `sigma = 0.25` and `Y = 7.48 xx 10^(10) N//m^(2)` ?

Explanation

To find the lateral contraction produced in the wire, we will follow these steps:

### Step 1: Calculate the Cross-Sectional Area of the Wire
The diameter of the wire is given as 1 mm, so the radius \( r \) is:
\[ r = \frac{1 \text{ mm}}{2} = 0.5 \text{ mm} = 0.5 \times 10^{-3} \text{ m} \]
The cross-sectional area \( A \) of the wire can be calculated using the formula for the area of a circle:
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