A rectangular metallic bar one metre long, one cm deep and one cm broad is placed on a smooth table. The Young's modulus and modulus of rigidity of metal of the bar are `2 xx 10^(11) N//m^(2)` and `8 xx 10^(10) N //m^(2)` respectively.
If now the base of the bar is rigidly clamped to the table, how will you apply a force of 500N, to produce shearing strain in the bar? Calculate the angle of deformation and the horizontal displacement produced in the top layer of the bar.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the given parameters
- Length of the bar (L) = 1 m
- Depth (Height) of the bar (H) = 1 cm = 0.01 m
- Breadth of the bar (B) = 1 cm = 0.01 m
- Young's Modulus (E) = \(2 \times 10^{11} \, \text{N/m}^2\)
- Modulus of Rigidity (G) = \(8 \times 10^{10} \, \text{N/m}^2\)
...