What should be the radius of a water drop so that the excess pressure inside it is 0.2 atm? Surface tension of water is `72 xx 10^(-3) N//m`?

Explanation

To find the radius of a water drop given the excess pressure and surface tension, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between excess pressure and radius**:
The excess pressure inside a droplet due to surface tension is given by the formula:
\[
P_{XS} = \frac{2T}{R}
...