What is the volume occupied bythe 64 gm of oxygen at standard pressure and at a temperature `27^(@)`. R `=8.31J // m o l //K ` ? Molar mass of oxygen = 32 gm.

Explanation

To find the volume occupied by 64 grams of oxygen at standard pressure and a temperature of 27°C, we will use the Ideal Gas Law, which is given by the equation:

\[ PV = nRT \]

Where:
- \( P \) = pressure (in pascals)
- \( V \) = volume (in cubic meters)
- \( n \) = number of moles of gas
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