Calculate the pressure exerted by hydrogen if the density of hydrogen is 0.09 `kg m^(-3)` and rms speed of hydrogen molecule at that presure is `1.84 kms^(-1)`.

Explanation

`rho = 0.09 kg m^(-3) , v_(rms) = 1.84 xx 10^(3) ms^(-1)`
Pressure `= P = ( 1)/( 3) rho v_(rms)^(2)`
`P = ( 1)/( 3) xx 0.09 xx ( 1.84xx 10^(3))^(2) = 1.015 xx 10^(5) N//m^(2)`