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A uniform wire 6m long weighing 0.04 kg ...

A uniform wire 6m long weighing 0.04 kg elongates by 0.8 mm when stretched by a load of 1 kg . If its density is 8.9 gm `//` cc, find the Young's modulus of the material.

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To find the Young's modulus of the material of the wire, we will follow these steps: ### Step 1: Understand the formula for Young's Modulus Young's modulus (Y) is defined as the ratio of stress to strain: \[ Y = \frac{\text{Stress}}{\text{Strain}} \] ### Step 2: Calculate the Stress Stress is defined as the restoring force per unit area. The restoring force (F) can be calculated using the weight of the load applied to the wire: \[ F = mg \] Where: - \( m = 1 \, \text{kg} \) (mass of the load) - \( g = 9.8 \, \text{m/s}^2 \) (acceleration due to gravity) So, \[ F = 1 \times 9.8 = 9.8 \, \text{N} \] ### Step 3: Calculate the Area of the Wire To find the area (A) of the wire, we can use the density (ρ) and mass (M) of the wire: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] The volume (V) can be expressed as: \[ V = A \times L_0 \] Where \( L_0 = 6 \, \text{m} \) (original length of the wire). Rearranging gives: \[ A = \frac{M}{\rho \times L_0} \] Given: - \( M = 0.04 \, \text{kg} \) - \( \rho = 8.9 \, \text{g/cm}^3 = 8900 \, \text{kg/m}^3 \) (converting to SI units) Now substituting the values: \[ A = \frac{0.04}{8900 \times 6} \] ### Step 4: Calculate the Strain Strain is defined as the change in length (ΔL) divided by the original length (L_0): \[ \text{Strain} = \frac{\Delta L}{L_0} \] Given: - \( \Delta L = 0.8 \, \text{mm} = 0.8 \times 10^{-3} \, \text{m} \) So, \[ \text{Strain} = \frac{0.8 \times 10^{-3}}{6} \] ### Step 5: Substitute values into Young's Modulus formula Now we can substitute the values of stress and strain into the Young's modulus formula: \[ Y = \frac{F/A}{\Delta L/L_0} \] ### Step 6: Calculate Young's Modulus Substituting the values we have: \[ Y = \frac{(9.8 \, \text{N}) / A}{(0.8 \times 10^{-3} \, \text{m}) / 6} \] ### Step 7: Final Calculation After calculating the area and substituting it back, we will find the Young's modulus value. ### Final Answer After performing the calculations, we find: \[ Y \approx 9.8 \times 10^{10} \, \text{N/m}^2 \]

To find the Young's modulus of the material of the wire, we will follow these steps: ### Step 1: Understand the formula for Young's Modulus Young's modulus (Y) is defined as the ratio of stress to strain: \[ Y = \frac{\text{Stress}}{\text{Strain}} \] ### Step 2: Calculate the Stress Stress is defined as the restoring force per unit area. The restoring force (F) can be calculated using the weight of the load applied to the wire: ...
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ICSE-PROPERTIES OF MATTER-MODULE 1 (ELASTICITY)FROM YOUNG.S MODULUS
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