A wire 0.1m long is placed horizontally on the surface of water and is gently pulled up with a force of `1.456 xx 10^(-2) N` to keep the wire in equilibrium. Calculate the surface tension of water.

Explanation

To calculate the surface tension of water using the given information, we can follow these steps:

### Step 1: Identify the given values
- Length of the wire (L) = 0.1 m
- Force (F) = 1.456 × 10^(-2) N

### Step 2: Understand the formula for surface tension
The formula for surface tension (γ) is given by:
\[ \gamma = \frac{F}{2L} \]
where:
- F is the force applied,
- L is the length of the wire in contact with the surface.

### Step 3: Substitute the values into the formula
Now, we can substitute the values of F and L into the formula:
\[ \gamma = \frac{1.456 \times 10^{-2}}{2 \times 0.1} \]

### Step 4: Calculate the denominator
First, calculate the denominator:
\[ 2 \times 0.1 = 0.2 \]

### Step 5: Perform the division
Now, we can perform the division:
\[ \gamma = \frac{1.456 \times 10^{-2}}{0.2} \]

### Step 6: Calculate the value
Calculating the above expression:
\[ \gamma = 1.456 \times 10^{-2} \div 0.2 = 0.0728 \, \text{N/m} \]

### Step 7: Round the answer
Rounding the value to two decimal places:
\[ \gamma \approx 0.073 \, \text{N/m} \]

### Final Answer
The surface tension of water is approximately **0.073 N/m**.

---