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The boiling point of liquid nitrogen is ...

The boiling point of liquid nitrogen is `- 195.81^(@)C` at atmospheric pressure. Express this temperature in (a) `""^(@)F` and (b) K.

Text Solution

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The correct Answer is:
`320.46^(@)F, 77.19K`
`t^(@)F = ( 9//5) ( - 195.81) + 32 = 320.46^(@)F. tK = 273 - 195.81 = 77.19K`
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