The dimesions of `(1)/(2)varepsilon_(0)E^(2)` (`varepsilon_(0)` is the permittivity of the space and E is electric field),is

Options

A. `MLT^(-1)`
B. `ML^(2)T^(-2)`
C. `ML^(-1)T^(-2)`
D. `ML^(2)T^(-1)`

Answer

c

Explanation

`epsi_(0)E - q//4pir^(2), epsi_(0)E^(2) = [F//r^(2)] = [ML^(-1) T^(-2)]` [ Note 1/2 `epsi_(0)E^(2)` is the energy stored per unit volume of an electric field = Energy /volume ` = ML^(2)T^(-2)//L^(3) = ML^(-1)T^(-2)]`.