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A man runs along the straight road for h...

A man runs along the straight road for half the distance with velocity `v_(1)` and the remaining half distance with velocity `v_(2)`. Then the average velocity is given by

A

`v_(1)v_(2)`

B

`v_(2)^(2)//v_(1)^(2)`

C

`(v_(1) + v_(2))//2`

D

`2v_(1)v_(2)//(v_(1) + v_(2))`

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The correct Answer is:
To find the average velocity of a man running half the distance with velocity \( v_1 \) and the other half with velocity \( v_2 \), we can follow these steps: ### Step-by-Step Solution 1. **Define the Total Distance**: Let the total distance be \( 2x \). This means the man runs half the distance \( x \) with velocity \( v_1 \) and the other half \( x \) with velocity \( v_2 \). 2. **Calculate Time for Each Half**: - For the first half (distance \( x \) with velocity \( v_1 \)): \[ t_1 = \frac{x}{v_1} \] - For the second half (distance \( x \) with velocity \( v_2 \)): \[ t_2 = \frac{x}{v_2} \] 3. **Calculate Total Time**: The total time \( T \) taken to cover the entire distance \( 2x \) is the sum of the times for both halves: \[ T = t_1 + t_2 = \frac{x}{v_1} + \frac{x}{v_2} \] 4. **Combine the Times**: To combine the two fractions, we can find a common denominator: \[ T = x \left( \frac{1}{v_1} + \frac{1}{v_2} \right) = x \left( \frac{v_2 + v_1}{v_1 v_2} \right) \] 5. **Calculate Average Velocity**: The average velocity \( V_{avg} \) is defined as the total distance divided by the total time: \[ V_{avg} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{2x}{T} \] Substituting the expression for \( T \): \[ V_{avg} = \frac{2x}{x \left( \frac{v_1 + v_2}{v_1 v_2} \right)} \] 6. **Simplify the Expression**: The \( x \) in the numerator and denominator cancels out: \[ V_{avg} = \frac{2}{\frac{v_1 + v_2}{v_1 v_2}} = \frac{2 v_1 v_2}{v_1 + v_2} \] ### Final Answer Thus, the average velocity of the man is: \[ V_{avg} = \frac{2 v_1 v_2}{v_1 + v_2} \]
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