A body falling from the rest has a velocity v after it falls through a heigh h. The distance it has to fall down further for its velocity to become double, will be

Options

A. 3h
B. 6h
C. 8 h
D. 10 h

Answer

a

Explanation

`v^(2) = 0^(2) + 2h, (2v)^(2) = 0^(2) + 2g(h + x)`
`(2v)^(2)//v^(2) = (h + x)//h , x = 3h`