A body of mass 5 kg is moving with a velocity of 20 m/s. If a force of 100 N is applied on it for 10 s in the same direction as its velocity, what will be the velociy of the body ?

Options

A. 200 m/s
B. 220 m/s
C. 240 m/s
D. 260 m/s

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Identify the given values
- Mass of the body (m) = 5 kg
- Initial velocity (u) = 20 m/s
- Force applied (F) = 100 N
- Time duration (t) = 10 s

### Step 2: Calculate the acceleration
Using Newton's second law of motion, we know that:
\[ F = m \cdot a \]
Where:
- F is the force,
- m is the mass,
- a is the acceleration.

Rearranging the formula to find acceleration (a):
\[ a = \frac{F}{m} \]

Substituting the known values:
\[ a = \frac{100 \, \text{N}}{5 \, \text{kg}} = 20 \, \text{m/s}^2 \]

### Step 3: Use the first equation of motion to find the final velocity
The first equation of motion states:
\[ v = u + a \cdot t \]
Where:
- v is the final velocity,
- u is the initial velocity,
- a is the acceleration,
- t is the time.

Substituting the known values:
\[ v = 20 \, \text{m/s} + (20 \, \text{m/s}^2 \cdot 10 \, \text{s}) \]
\[ v = 20 \, \text{m/s} + 200 \, \text{m/s} \]
\[ v = 220 \, \text{m/s} \]

### Final Answer
The final velocity of the body after 10 seconds is **220 m/s**.

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