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A particale moves under the effect of a ...

A particale moves under the effect of a force `F = Cx` from `x = 0` to `x = x_(1)`. The work down in the process is

A

`cx_(1)^(2)`

B

`(1)/(2)cx_(1)^(2)`

C

`x = x_(1)`

D

none of above

Text Solution

Verified by Experts

The correct Answer is:
b
`W = int_(0)^(x_(1)) Cx dx = (1//2) Cx_(1)^(2)`
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