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A particle is projected making angle 45^...

A particle is projected making angle `45^@` with horizontal having kinetic energy K. The kinetic energy at highest point will be : -

A

`(K)/(2)`

B

`(K)/(sqrt(2))`

C

K

D

zero

Text Solution

Verified by Experts

The correct Answer is:
a
K.E. ` = (1//2)mv_(0)^(2) cos^(2) 45 = K xx (1//2)`
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