A 40kg slab rest on a frictionless floor as shown in . A 10kg blocks rests on the top of the slab. The static coefficient of friction between the block and the slab is `0.60`, while kinetic friction is `0.40`. The 10kg block is acted upon by a horizontal force of 100N. What is the resulting acceleration of the slab ?

Options

A. `0.98m//s^(2)`
B. `1.47m//s^(2)`
C. `1.52m//s^(2)`
D. `6.1m//s^(2)`

Answer

a

Explanation

`a = mu mg //40 = 0.4 xx 10 xx 9.8//40 = 0.98ms^(-2)`