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A block of mass 2 kg is placed on the fl...

A block of mass 2 kg is placed on the floor. The coefficient of static friction is 0.4. A force F of 2.5 N is applied on the block as shown in Fig. 15.4.4. The force of friction between the block and the floor is `(g = 9.8 m//s^(2))`

A

1.5 N

B

0.5 N

C

2.5 N

D

None of the above

Text Solution

Verified by Experts

The correct Answer is:
c
`f_(s) = mu_(s) R = 4 xx R = 4 xx 2 xx .9.8 = 7.84` N
The block is not moving, So the frictional force ` = 2.5` N
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