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The viscous drag on a spherical body mov...

The viscous drag on a spherical body moving with a speed v is proportional to

A

`sqrt(v)`

B

v

C

`1//sqrt(v)`

D

`v^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the viscous drag on a spherical body moving with a speed \( v \), we can refer to Stokes' Law. Here’s a step-by-step solution: ### Step 1: Understand Stokes' Law Stokes' Law states that the viscous drag force \( F \) experienced by a spherical object moving through a viscous fluid is given by the equation: \[ F = 6 \pi \eta r v \] where: - \( F \) is the viscous drag force, - \( \eta \) is the dynamic viscosity of the fluid, - \( r \) is the radius of the sphere, - \( v \) is the velocity of the sphere. ### Step 2: Identify the Proportionality From the equation, we can see that the viscous drag force \( F \) is directly proportional to the velocity \( v \) of the spherical body. This means: \[ F \propto v \] ### Step 3: Conclusion Thus, the viscous drag on a spherical body moving with a speed \( v \) is proportional to \( v \). ### Final Answer The viscous drag on a spherical body moving with a speed \( v \) is proportional to \( v \). ---
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