A gestationary satellite is orbiting the earth at a height 6 R above the surface of earth, where R is the radius of the earth. The time period of another statellight at a height of 2.5 R from the surface of earth in hours is

Options

A. `6sqrt(2)` hr
B. 6 hr
C. `5sqrt(2)` hr
D. 10 hr

Answer

A

Explanation

`(T_(1)//T_(2)) = (r_(1)//r_(2))^(3//2), r_(1) = 6R + R + 7R`
`r_(2) 2.5 R + R = 3.5 R`,
`T_(2) = 24 (3.5 R?/7R)^(3//2) = 6sqrt(2)` hours